Flex India has announced a job notification for the Junior Engineer. The student from Electronics and Communication and Electrical Engineering branch can apply for Flex Recruitment 2021. Interested and eligible candidates can read more details below.

Flex Recruitment 2021

Organization Name Flex 
Post Name Junior Engineer
Salary  ₹ 3.4 Lakhs to ₹ 4.3 Lakhs
Job Location Pune, MH

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Job Description:

Flex India is conducting an interview for the post of Junior Engineer.

Job Responsibilities:

  • Creating setup like product Number, BOM Structure, etc in AGILE and BAAN for new Products
  • Creating part numbers for BOM in agile & Baan
  • Creating AVL in agile & Baan system
  • Downloading customer documents like product specifications etc & releasing same in CDC
  • Work as a Change Analysts during NPI for new changes
  • Release Part list to production for new models and after implementation of ECO’s
  • Efficiently managing ECOs for manufacturing sites across the globe

Eligibility Criteria:

  • Minimum  0- 2 years of experience in a manufacturing setup, preferably in the EMS industry
  • B.E Electronics and Communication Engineering / EEE / Mechanical

Preferred skill:

  • Knowledge of electrical and electronic components
  • Excellent written and oral communication skills MANDATORY.
  • Working Knowledge of MS Office tools (MS Excel, MS Word)
  • Good team player

About Flex

Flex builds great products for customers that create value and improve people’s lives. Building on our 50+ year history of manufacturing, the ~160,000-member Flex Family across 30 countries is at the heart of everything we do.

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